Question

sinA-cosA+1/sinA+cosA-1= cosA/1-sinA​

Answer 1

Step-by-step explanation:

It is a common question in Trigonometry , we can found this in many books and exams.

Here is the solution -

=(sinA + 1 - cosA) / (cosA - 1 + sinA)

Divide each term by cosA

=(tanA + secA - 1) / (1 - secA + tanA)

=[tanA + secA - ( sec2A−tan2Asec2A−tan2A)] /

( 1 - secA + tanA)

= (tanA+secA)( 1 - secA + tanA )/(1 - secA + tanA)

= tanA + secA

= (sinA / cosA )+ 1 / cosA

= (sinA + 1 )/ cosA

Hence Proved

Hope it will help you

Answer 2

Step-by-step explanation:

we are get given the prove the following trigonometry equal

$\sin0 + 1 - \cos0 = 1 + \sin0$