sinA-cosA+1 ÷sinA + cosA-1=cosA÷1-sinA
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Hey
Sin∅ - Cos∅ + 1 / Sin∅ + Cos∅ - 1
=( Sin∅ + 1 - Cos∅ )( Sin∅ + 1 + Cos∅ )
divided by
( sin∅ + Cos∅ - 1 ) ( Sin∅ + Cos∅ + 1 )
NoTe :- Here we multiplied the numerator and denominator by same term .
= ( Sin∅ + 1 )² - Cos²∅/ ( Sin∅ + Cos∅)² -1
= Sin²∅ + 1 + 2Sin∅ - Cos²∅ / Sin²∅ + Cos²∅ + 2Sin∅.Cos∅ - 1
= Sin²∅ + 2Sin∅ + ( 1 - Cos²∅ ) / ( Sin²∅ + Cos²∅ ) + 2Sin∅ Cos∅ - 1
= Sin²∅ + 2Sin∅ + Sin²∅ / 1 - 1 + 2Sin∅Cos∅
= 2Sin²∅ + 2Sin∅ / 2Sin∅ . Cos∅
= 2 Sin∅ ( Sin∅ + 1 ) / 2Sin∅ .Cos∅
= Sin∅ + 1 / Cos∅
thanks :)
Sin∅ - Cos∅ + 1 / Sin∅ + Cos∅ - 1
=( Sin∅ + 1 - Cos∅ )( Sin∅ + 1 + Cos∅ )
divided by
( sin∅ + Cos∅ - 1 ) ( Sin∅ + Cos∅ + 1 )
NoTe :- Here we multiplied the numerator and denominator by same term .
= ( Sin∅ + 1 )² - Cos²∅/ ( Sin∅ + Cos∅)² -1
= Sin²∅ + 1 + 2Sin∅ - Cos²∅ / Sin²∅ + Cos²∅ + 2Sin∅.Cos∅ - 1
= Sin²∅ + 2Sin∅ + ( 1 - Cos²∅ ) / ( Sin²∅ + Cos²∅ ) + 2Sin∅ Cos∅ - 1
= Sin²∅ + 2Sin∅ + Sin²∅ / 1 - 1 + 2Sin∅Cos∅
= 2Sin²∅ + 2Sin∅ / 2Sin∅ . Cos∅
= 2 Sin∅ ( Sin∅ + 1 ) / 2Sin∅ .Cos∅
= Sin∅ + 1 / Cos∅
thanks :)
Anonymous:
tnx ayush..
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