Math, asked by sanghamitapattnaik56, 19 days ago

sinA-cosA+1/sinA+cosA-1=cosA/1-sinA

Answers

Answered by visheshsingh62

0

Answer:

L.H.S=

cosA+sinA−1

1−cosA+sinA

×

cosA+sinA−1

cosA+sinA−1

=

(cosA+sinA)

2

−1

cosA+sinA+1−cos

2

A−cosAsinA−cosA+sinAcosA+sin

2

A+sinA

=

cos

2

A+sin

2

A+2cosAsinA−1

1−cos

2

A+sin

2

A+2sinA

=

1+2cosAsinA−1

2sin

2

A+2sinA

=

2cosAsinA

2sinA(sinA+1)

=

cosA

(sinA+1)

=R.H.S

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