Question

SinA-cosA+1/sinA+cosA-1=secA+tanA
Prove.

Answer 1

Step-by-step explanation:

LHS

devide cosA in both numerator & deniminator

(tanA-1+secA/tanA+1-secA)× (tanA-secA/tanA-secA)

={(tanA+secA)-1}/(tanA-secA+1) ×tanA-secA/tanA-secA

=tan²A-sec²A-tanA+secA/ (tanA-secA+1)(tanA-secA)

=-(1+tanA-secA)/ (tanA-secA+1)(tanA-secA)

=-1/tanA-secA

=1/secA-tanA×secA+tanA/secA+tanA

=secA+tanA/sec²A-tan²A

=secA+tanA

Answer 2

Hope this will Help u Dear