Math, asked by Sayeezh1465, 11 months ago

(Sina+cosa)(1-sinacosa)=sin3a+cos3a

Answers

Answered by SantoshDaultaniSD
8

Answer:

L.H.S. = (sinA + cosA)(1 - sinA*cosA)

= sinA - sin^2A * cosA + cosA - sinA * cos^2A

= sinA - sinA * cos^2A + cosA - sin^2A * cosA

= sinA(1 - cos^2A) + cosA(1 - sin^2A)

= sinA * sin^2A + cosA * cos^2A

= sin^3A + cos^3A

= R.H.S. Proved Ans

Answered by Satish62060
0

Answer:

Step-by-step explanation:

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