( SinA + CosA)²= 1+2 SinA×CosA
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i think we have to prove formula which is most important
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Explanation:
we need to prove that,
( SinA + CosA)²= 1+2 SinA×CosA
therefore, we know,
{(a+b)^2=a^2+b^2+2ab}
from that equation; we get;
sin^2A+cos^2A+2SinA×CosA
(sin^2A+cos^2A)+2sinAcosA
now,
we know that ,
{sin^2A+cos^2A = 1}
from this we get;
1+2SinA×CosA
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