(SinA+cosA)^2=1+sinA×cosA
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Answer:
Step-by-step explanation:
n LHS we have
(sinA+cosA)
2
=sin
2
A+2sinAcosA+cos
2
A
∵sin
2
A+cos
2
A=1, we get
=1+2sinAcosA
We know, 2sinAcosA=sin2A
=1+sin2A
Which is equal to RHS, hence proved.
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