Math, asked by abbasdemroth, 1 year ago

- (sinA+COSA)²-2sinAcosA is equal to:

Answers

Answered by chaudharyragini4

Step-by-step explanation:

-(sinA

$- ({ {sina}^{2} +{ cos a}^{2} + 2sinacosa}) - 2sinacosa \\ - 1 - 2sinacosa - 2sinacosa \\ - 1 - 2sin2a$

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