Math, asked by chitti1062, 1 month ago

sinA+cosA=√2 find sinA cos A​

Answers

Answered by judith0209
1

Answer:

sinAcosA = 1/2

Step-by-step explanation:

sinA + cosA =√2

Squaring both sides we get,

(sinA + cosA)² = (√2)²

sin²A + cos²A + 2sinAcosA = 2-------[(a + b)²= a² + b² + 2ab]

1 + 2sinAcosA = 2--------------(sin²A + cos²A = 1 )

2sinAcosA = 2-1

2sinAcosA = 1

sinAcosA = 1/2

Therefore the value of sinAcosA is 1/2.

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