sinA+cosA=√2 find sinA cos A
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Answer:
sinAcosA = 1/2
Step-by-step explanation:
sinA + cosA =√2
Squaring both sides we get,
(sinA + cosA)² = (√2)²
sin²A + cos²A + 2sinAcosA = 2-------[(a + b)²= a² + b² + 2ab]
1 + 2sinAcosA = 2--------------(sin²A + cos²A = 1 )
2sinAcosA = 2-1
2sinAcosA = 1
sinAcosA = 1/2
Therefore the value of sinAcosA is 1/2.
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