( sinA + cosA)²+(sinA - cosA²)
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secA + tanA = x

From now on I will just let s = sinA

Treating this as a quadratic with variable s and x is a constant we get:

Solving using the quadratic formula:


If sinA = – 1 then A = 270 degrees so since sec270 and tan270 are infinite the only answer seems to be:

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