Question

SinA +CosA=2 then
what is 2 sinAcosA

Answer 1

Answer:

Step-by-step explanation:

sinA + cosA =2                                           (squaring on both side)

(sinA + cosA)^2 = (2)^2

sin^2A + cos^2A + 2sinAcosA = 4            (sin^2A + cos^2A=1)

1+2sinAcosA=4

2sinAcosA= 4-1

2sinAcosA=3