Math, asked by debanshumondal588, 5 hours ago

sinA-cosA= √3-1/2,then find
SinACosA​

Answers

Answered by devindersaroha43
1

Answer:

Step-by-step explanation:

SinA-CosA =(√3–1)/2

Squaring both sides

Sin^2A + Cos^2A -2SinACosA = (3+1–2√3)/4 ——eq1

Sin^2A + Cos^2A =1 (Remember this property)

Putting the value of Sin^2A + Cos^2A in eq1

1–2sinACosA = (3+1–2√3)/4

Using basic mathematics you can get the value of SinACosA as √3/4

Hope you understood. ☺

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