Question

sinA+cosA=√3. Then prove that tanA+cotA=1

Answer 1

SinA + cosA = √3

On squaring  we get,

(SinA + cosA)² = (√3)²

Sin²A + cos²A +2sinAcosA = 3

1 + 2sinAcosA = 3

2sinAcosA = 3-1

SinAcosA = 2/2

sinAcosA = 1......................(1)

tanA+cotA = 1

sinA/cosA + cosA/sinA = 1

sin²A + cos²A /sinAcosA = 1

1/sinAcosA = 1

sinAcosA = 1.....................(2)

From (1) and (2),

tanA + cotA = 1

Answer 2

Hii there!!! Here is your solution.