SinA +CosA =√3 to prove tanA + cotA =1
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hence it is proved that tanA+cotA=1
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sinA+cosA = √3
squaring both sides
(sinA + cosA)² = 3
1+2sinAcosA = 3
2sinAcosA = 2
sinAcosA = 1
Now
tanA + cotA
=1/sinAcosA
=1/1
=1
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