sinA+cosA=a then sinA-cosA=?
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Answered by
1
sinA=a-cosA.... eq (1)
cosA=a-sina... eq (2)
sinA-cosA=0
a-cosA-cosA=0.....(1,se)
-2cosA=-a
cosA=a/2
again..put in eq (2)
a/2=a-sinA
-sinA=a/2-a
sinA=a/2
from question
sinA-cosA=a/2-a/2=0
is your answer
cosA=a-sina... eq (2)
sinA-cosA=0
a-cosA-cosA=0.....(1,se)
-2cosA=-a
cosA=a/2
again..put in eq (2)
a/2=a-sinA
-sinA=a/2-a
sinA=a/2
from question
sinA-cosA=a/2-a/2=0
is your answer
Answered by
2
Answer is 2-a
Hope you find the right answer or this is terribly wrong
Hope you find the right answer or this is terribly wrong
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