sinA=cosA/cotA
it is right ?
Answers
Answered by
1
Answer:
Yes
Step-by-step explanation:
cotA - cosA/sinA
cosA/cotA - cosA/CosA ×SinA
So, cosA/cotA - SinA
Hope it help
Answered by
2
multiple sina with sina/sina
sina ×sina/sina
=sin2a/sina
1-sin2a/sina
no it's not right
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