sinA=cosA , find the value if 4+5tan sq. A/7
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Given
sinA = cosA
=> ( sinA/cosA ) = 1
=> tanA = 1
=> tanA = tan 45°
=> A = 45°
Now ,
Value of (4 + 5tan² A )/7
= ( 4 + 5 tan² 45)/7
= (4 + 5 )/7
= 9/7
••••
sinA = cosA
=> ( sinA/cosA ) = 1
=> tanA = 1
=> tanA = tan 45°
=> A = 45°
Now ,
Value of (4 + 5tan² A )/7
= ( 4 + 5 tan² 45)/7
= (4 + 5 )/7
= 9/7
••••
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