sinA+cosA=P and secA+cosecA=Q show thatQ(p square -1) = 2P
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Step-by-step explanation:
LHS =Q (p square-1)
=SecA+cosecA[(sinA+cosA)square-1]
=secA+cosecA(sin squareA+cos squareA+2sinAcosA-1)
=secA+cosecA(1+2sinAcosA-1)
=1/cosA(2sinAcosA)+1/sinA(2sinAcosA)
=2sinA+2cosA
=2(sinA+cosA)
RHS=2p
=2(sinA+cosA)
LHS=RHS
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