sinA+CosA= P and secA+cosecA=q to prove kare p2-1= 2p/q
Answers
Answered by
3
Step-by-step explanation:
we have, sinA+cosA = p
and secA+cosecA = q
to prove, p²-1 = 2p/q
LHS, p²-1
put the value of p,
= (sinA+cosA)²-1
= sin²A+cos²A+2sinAcosA -1
as, sinA+cosA = 1
so, = 1 +2sinAcosA -1
and 2sinAcosA = sin2A
so, = 1+ sin2A -1
= sin2A
RHS, 2p/q
put the value of p and q,
= 2(sinA+cosA)/(secA+cosecA)
= 2(sinA+cosA)/(1/cosA+1/sinA)
= 2(sinA+cosA)sinAcosA/(sinA+cosA)
= 2sinAcosA
= sin2A
so, LHS = RHS
hence, proved
Answered by
1
Plz check the answer below I gave a pic.... Hope it help you... Also plz mark me as brainliest
Attachments:
Similar questions
French,
6 months ago
Math,
6 months ago
Hindi,
1 year ago
Math,
1 year ago
Computer Science,
1 year ago