Math, asked by devraj9788, 1 year ago

sinA+CosA= P and secA+cosecA=q to prove kare p2-1= 2p/q​

Answers

Answered by rinkum57
3

Step-by-step explanation:

we have, sinA+cosA = p

and secA+cosecA = q

to prove, p²-1 = 2p/q

LHS, p²-1

put the value of p,

= (sinA+cosA)²-1

= sin²A+cos²A+2sinAcosA -1

as, sinA+cosA = 1

so, = 1 +2sinAcosA -1

and 2sinAcosA = sin2A

so, = 1+ sin2A -1

= sin2A

RHS, 2p/q

put the value of p and q,

= 2(sinA+cosA)/(secA+cosecA)

= 2(sinA+cosA)/(1/cosA+1/sinA)

= 2(sinA+cosA)sinAcosA/(sinA+cosA)

= 2sinAcosA

= sin2A

so, LHS = RHS

hence, proved

Answered by bikashlakhya2003
1

Plz check the answer below I gave a pic.... Hope it help you... Also plz mark me as brainliest

Attachments:
Similar questions