(sinA+cosA)(secA+cosecA)=2+secA cosecA
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(sinA+cosA)(secA+cosecA)
=(sinA+cosA){(1/cosA)+(1/sinA)}
={(sinA+CosA)(sinA+cosA)}/{sinA×cosA}
=(sinA+cosA)²/(sinA×cosA)
=(sin²A+cos²A+2sinAcosA)/(sinA×cosA)
=(1+2sinAcosA)/(sinA×cosA)
=2+secAcosecA
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