Question

sinA + COSA/
SECA + coseCA=

SINA. COSA​

Answer 1

Answer:

Solution :

____________________________________________________________

Given :

To prove :

(Sin A + Cos A)(Sec A + Cosec A)= 2 + Sec A Cosec A

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We know that,

⇒

&

⇒

______________________________

Proof :

LHS = (Sin A + Cos A)(Sec A + Cosec A)= 2 + Sec A Cosec A

⇒

⇒

⇒

⇒

__________

We also know that,

⇒ Sin² A + Cos² A = 1

_________________

Hence,

 ⇒

⇒

⇒

⇒

⇒

⇒ 2 + Sec A Cosec A

⇒ RHS

                                            ∴ LHS = RHS

                                         ∴ Hence, Proved,.

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                                        Hope it Helps !!

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