Question

sinA+cosA/secA+cosecA=sinA.cosA​

Answer 1

Step-by-step explanation:

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Answer 2

$\huge\underline{\bf \orange{Solution :}}$

$\sf \implies \frac{ \sin A + \cos A}{ \sec A+ \csc A} = \sin A. \cos A \\ \\ \sf \implies\frac{ \sin A+ \cos A}{ \frac{1}{ \cos A} + \frac{1}{ \sin A} } = \sin A. \cos A \\ \\ \sf \implies\frac{ \sin A+ \cos A}{ \frac{ \sin A+ \cos A}{ \sin A .\cos A} } = \sin A. \cos A \\ \\ \sf \implies \sin A. \cos A = \sin A. \cos A$