Question

(sinA-cosA) (sinA+cosA)= ?


plz ans in brief ​

Answer 1

(Sin a - Cos a) ( Sin a + Cos a) =>

Sin^2 a - Cos^a  (As we know (a -b) (a+b) = (a^2 - b^2)

so , sin^a - cos^a = 1 (Identity)

hence our Answer is 1

Answer 2

Answer:

(sinA-cosA) (sinA+cosA)=

$\sin2(a) - \cos2(a)$

Step-by-step explanation:

sin squire A-- cos squire A = 1

is not correct.

because,

sin squire A + cos squire A = 1