Sina+cosa/sina-cosa+sina-cosa/sina+cosa=1-2cos2a=2/2sin2a-1
Answers
Answered by
15
(sinA+cosA)/(sinA-cosA). + (sinA-cosA)/(sinA+cosA)
Taking LCM
{(sinA+cosA)^2 + (sinA-cosA)^2} / (sinA+cosA)(sinA-cosA)
(sin^2A + cos^2A +2sinAcosA +sin^2A+cos^2A-2sinAcosA)/(sin^2A-cos^2A)
=. -(1+1)/cos2A
=2/2sin^2A-1
=2/1-2cos^2A
Taking LCM
{(sinA+cosA)^2 + (sinA-cosA)^2} / (sinA+cosA)(sinA-cosA)
(sin^2A + cos^2A +2sinAcosA +sin^2A+cos^2A-2sinAcosA)/(sin^2A-cos^2A)
=. -(1+1)/cos2A
=2/2sin^2A-1
=2/1-2cos^2A
Similar questions