sina + cosa \sina - cosa + sina - cosa \sina + cosa
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Answer:
sinA−cosA
sinA+cosA
+
sinA+cosA
sinA−cosA
=
(sinA−cosA)(sinA+cosA)
(sinA+cosA)
2
+
(sinA−cosA)(sinA+cosA)
(sinA−cosA)
2
=
sin
2
A−cos
2
A
sin
2
A+cos
2
A+2sinAcosA+sin
2
A+cos
2
A−2sinAcosA
=
sin
2
A−cos
2
A
2
=
sin
2
A−(1−sin
2
A)
2
=
2sin
2
A−1
2
=
2(1−cos
2
A)−1
2
=
1−2cos
2
A
2
Step-by-step explanation:
hopefully this will help you ❤️
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