(sinA+cosA)(TanA+cotA)= secA+CosecA
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Answer:(sinA+cosA) (sinA/cosA+cosA/sinA)
Answer:(sinA+cosA) (sinA/cosA+cosA/sinA) (sinA+cosA)(1/sinAcosA)
Answer:(sinA+cosA) (sinA/cosA+cosA/sinA) (sinA+cosA)(1/sinAcosA) sinA/sinAcosA+cosA/sinAcosA
Answer:(sinA+cosA) (sinA/cosA+cosA/sinA) (sinA+cosA)(1/sinAcosA) sinA/sinAcosA+cosA/sinAcosA1/cosA+1/sinA
Answer:(sinA+cosA) (sinA/cosA+cosA/sinA) (sinA+cosA)(1/sinAcosA) sinA/sinAcosA+cosA/sinAcosA1/cosA+1/sinAsecA+cosecA
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