SinA × CosA=½ then find (SinA+CosA)
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Answer:
√2
Step-by-step explanation:
(SinA+CosA) = √(SinA+CosA)²
= √[Sin²A + Cos²A + 2SinACosA]
= √ [1 + 2SinACosA)
= √ (1 + 2*1/2) = √ (1 + 1) = √2
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