Sina+cosa=x. Sin^3+cos^3=y
Then required equationwhat
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Heya!!
Sin a + Cos a = x
SQUARING BOTH SIDE'S
2 Sin a × Cos a = x² -1
Sin a × Cos a = ( x² - 1 ) /2
_______________________________
Sin³ a + Cos ³ a = y
=>
( Sin a + Cos a )³ - 3 Sin a × Cos a ( Sin a
Cos a )
=>
y = x³ - 3 Sin x Cos a { x }
=>
y = x³ -3x Sin a × Cos a
=>
y = x³ - 3 ( x² - 1 ) /2
=>
2y = 2x³ - 3x² + 3
=>
2x³ - 3x² - 2y + 3 = 0
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