Question

sinA+cosA=x then find sinA-cosA=?

Answer 1

Step-by-step explanation:

$sinA + cosA = x \\ Squaring \: on \: both \: sides \\ {sin}^{2} A + {cos}^{2} A + 2sinA \: cosA = {x}^{2} \\ 1 - {cos}^{2} A + 1 - {sin}^{2} A + 2sinA \: cosA = {x}^{2} \\ 2 - {x}^{2} = {cos}^{2} A + {sin}^{2} A - 2sinA \: cosA \\ 2 - {x}^{2} = ( {sinA - cosA)}^{2} \\ sinA - cosA = + \sqrt{2 - {x}^{2} } \:, - \sqrt{2 - {x}^{2} } \\ \\ Hope \: it \: will \: help \: you.$