Question

sinA+CosB = 2, find the value of sin (A+B) + cos (A-B)
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Answer 1

Answer:

1

Step-by-step explanation:

sin(A+B) +cos(A-B)

sinA+sinB +cosA-cosB

A=60,B=30

sin60+sin30+cos60-cos30

√3/2+1/2+1/2-√3/2

+1/2+1/2

2/2

1

Answer 2

Answer:

Let A=45°and B=20

Sin(45°-30°)=sin45°cos 30°_cos 45°sin 30°

Sin (15°)=1/3×/3/2-1/2×1/2

=/3/2/2-1/2/2= (/3-1)/2/2

Step-by-step explanation:

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