Question

"sinA.cosB+cosA.sinB" given (sinA=1/√2, sinB=√3/2)

Answer 1

SinA CosB + cosA SinB can be written as SinA +SinB
Substitute the value of sina and sinb.

Answer 2

Answer

Here we know that sin45°=1/√2

and sin60°=√3/2

Therefore

Putting A=45° and B=60°

Now from the equation

SinA.cosB+cosA.sinB

Sin45°.cos60°+cos45°.sin60°

1/√2.1/2+1/√2.√3/2

1/√2(1/2+√3/2)

1/√2. (1+√3/2)

Bus ab isko rationalise kr le