"sinA.cosB+cosA.sinB" given (sinA=1/√2, sinB=√3/2)
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SinA CosB + cosA SinB can be written as SinA +SinB
Substitute the value of sina and sinb.
Substitute the value of sina and sinb.
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Answer
Here we know that sin45°=1/√2
and sin60°=√3/2
Therefore
Putting A=45° and B=60°
Now from the equation
SinA.cosB+cosA.sinB
Sin45°.cos60°+cos45°.sin60°
1/√2.1/2+1/√2.√3/2
1/√2(1/2+√3/2)
1/√2. (1+√3/2)
Bus ab isko rationalise kr le
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