Question

sinA+cosecA=2 ,then find sin^100A+cosec^100A.​

Answer 1

$\sin \alpha+\csc \alpha=2\\\\\sin \alpha+\dfrac{1}{\sin \alpha}=2\\\\\sin^2 \alpha +1=2\sin \alpha\\\sin^2 \alpha -2\sin \alpha+1=0\\(\sin \alpha -1)^2=0\\\sin \alpha-1=0\\\sin \alpha=1\\\\\sin^{100}\alpha+\csc^{100}\alpha=1+\dfrac{1}{1}=2$

Answer 2

PLEASE MARK AS BRAINLIEST!!!