sinA.cotB.sinB + cotA. sinB. sinA = sin(A + B)
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L.H.S. = sinA.cotB.sinB + cotA.sinB.sinA
L.H.S. = sinA.cosB/sinB.sinB + cosA/sinA.sinB.sinA
L.H.S. = sinA.cosB + cosA.sinB
L.H.S. = sin(A+B)
(There's and identity for compound angles, it goes like sin(A+B)= sinA.cosB + cosAsinB)
L.H.S. = R.H.S.
Hence proved.
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