SinA =root3/2 and find the value of 2cot2A-1
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sinA=root3/2
Therefore,
P=root3
H=2
Therefore,
H^2=P^2+B^2
(root3) ^2=2^2+B^2
3-2=B^2
B=root1
2cot^2A-1= 2×(1/root3)^2-1
2×1/3-1
-1/2
Therefore,
P=root3
H=2
Therefore,
H^2=P^2+B^2
(root3) ^2=2^2+B^2
3-2=B^2
B=root1
2cot^2A-1= 2×(1/root3)^2-1
2×1/3-1
-1/2
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