Math, asked by sandip191, 1 year ago

(sinA+secA)^2+(cosA+cosec)^2=(1+secAcosecA)^2

Answers

Answered by Jennydsilva
4
Identities used:
cos²A+sin²A=1
sinAsecA=sinA*1/cosA=tanA
Similarly, cosAcosecA=cotA
cotA=1/tanA
cosecA=1/sinA & secA= 1/cosA
tan²A+1=sec²A
sec²A/tanA= 1/cos²A*cosA/sinA=1/sinA*1/cosA=secAcosecA
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