Question

(sinA+secA)^2+(cosA+cosecA) ^2=(1+secAcosecA) ^2..
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Answer 1

Step-by-step explanation:

RHS should be (1+SecA.CosecA)2.

LHS= (SinA +1/CosA)2 +(CosA+ 1/SinA)2

=((SinACosA +1)/CosA)2 +((SinACosA +1)/SinA)2

=(SinACosA +1)2/Cos2A +(SinACosA+1)2/Sin2A

=(SinACosA +1)2 {1/Cos2A +1/Sin2A}

=(SinACosA +1)2 {Sin2A +Cos2A /Sin2 A Cos2 A}

=(SinACosA +1)2 {1/Sin2 A Cos2 A)

=( SinA Cos A/SinA Cos A +1/SinA Cos A)2

=(1+CosecA.SecA)2

=RHS

Answer 2

Step-by-step explanation:

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