Question

sinA . sin(60-A) . sin(60+A) = 1/4 sin3A

Answer 1

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Answer 2

Answer:

1/4 sin3A

Step-by-step explanation:

LHS = sinA . sin(60° + A) . sin(60° - A)

= 1/2 sinA.[2sin(60° + A).sin(60° - A)]

= 1/2 sinA.[cos{(60° + A) - (60° - A)} - cos{( 60° + A) + (60° - A)}]

= 1/2 sinA.[cos(60° + A - 60° + A) - cos120° ]

= 1/2 sinA.[cos2A - {- 1/2}]

= 1/2 sinA.[cos2A + 1/2]

= 1/2 sinA. cos2A + 1/4 sinA

= 1/4 ( 2cos2A.sinA)+1/4 sinA

= 1/4[sin(2A+A) - sin(2A - A)] + 1/4 sinA

= 1/4(sin3A-sinA) + 1/4 sinA

= 1/4 sin3A - 1/4 sinA + 1/4 sinA

= 1/4 sin3A