Question

SinA. Sin(B-C) + SinB. Sin(C-A) SinC . Sin(A-B) = 0​

Answer 1

Answer:

SinA . Sin(B - C) + SinB . Sin(C - A) + SinC . Sin(A - B)=0

=>SinA . (SinBCosC - CosBSinC) + SinB . (SinCCosA - CosCSinA) + SinC . (SinACosB - CosASinB)

=>SinASinBCosC -SinACosBSinC + SinBSinCCosA - SinBCosCSinA + SinCSinACosB - SinCCosASinB

All get cancelled

=> 0 (Proven)

HOPE IT HELPS! PLEASE MARK MY ANSWER AS THE BRAINLIEST : )

Answer 2

Answer:

I hope you understand this