sinA + sin2A/cosA-cos2A=cot A/2
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Answer:
sinA+ sin2A/cosA-cos2A
= 2sin(A+2A/2) cos(2A-A/2)/
2sin(2A+A/2)sin(2A-A/2)
=2sin(3A/2)cos(A/2)/
2sin(3A/2)sin(A/2)
=cos(A/2)/
sin(A/2)
=cot(A/2)
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