Math, asked by shanks17, 1 year ago

sinA+Sin2A+Sin4A+Sin5A/CosA+Cos2A+Cos4A+Cos5A=Tan3A
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Answers

Answered by ᎷíssGℓαмσƦσυs

3

Answer:

sinA+sin2A+sin4A+sin5A/cosA+cos2A+cos4A+cos5A

=2sin3A.cos2A+2sin3A.cosA/2cos3A.cos2A+2cos3A.cosA

=2sin3A(cos2A+cosA)/2cos3A(cos2A+cosA)

=tan3A

proved

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