Math, asked by SomanSaroj, 6 months ago

sinA + sin3A + sin5A + sin 7A =

Answers

Answered by kushisai19

2

Answer:

answer is this bro 4cosAcos2Asin4A

Step-by-step explanation:

sinA+sin3A+sin5A+sin7A=(sinA+sin3A)+(sin5A+sin7A)

=2sin(2A+3A)cos(23A−A)+2sin(25A+7A)cos(27A−5A)

=2sin2AcosA+2sin6AcosA=2cosA(sin2A+sin6A)

=2cosA(2sin(22A+6A)cos(26A−2A))

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