Math, asked by rajanigandhamaryada, 8 months ago

SinA+Sin5A+Sin9A÷CosA+Cos5A+Cos9A​

Answers

Answered by MrEccentric
18

★☆〖Qบęຮτ ı¨ ø nˇ〗☆★

sinA+sin5A+sin9A

=

(cosA+coa9A)+cos5A

(sin9A+sinA)+sin5A

=

2cos(2A+9A ).cos(29A−A )+cos5A

2sin(

2

A+9A

)cos(

2

9A−A

)+sin5A

=

2cos5Acos4A+cos5A

2sin5Acos4A+sin5A

=

cos5A(2cos4A+1)

sin5A(2cos4A+1)

= tan 5A

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Answered by leenasingh12284
2

Step-by-step explanation:

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