SinA+Sin5A+Sin9A÷CosA+Cos5A+Cos9A
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sinA+sin5A+sin9A
=
(cosA+coa9A)+cos5A
(sin9A+sinA)+sin5A
=
2cos(2A+9A ).cos(29A−A )+cos5A
2sin(
2
A+9A
)cos(
2
9A−A
)+sin5A
=
2cos5Acos4A+cos5A
2sin5Acos4A+sin5A
=
cos5A(2cos4A+1)
sin5A(2cos4A+1)
= tan 5A
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