SinA+SinB÷1-SinA+SinB if tanA=1÷2 and CosB=3÷2
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The Question can be written as sinA+sinB-sinA+sinB= 2sinB
cosB=3/2 so sinB=√(1-cos^2B)= √(1-9/4)
=-5/4
Therefore 2sinB=2×-5/4=-5/2
Hope this helps u
cosB=3/2 so sinB=√(1-cos^2B)= √(1-9/4)
=-5/4
Therefore 2sinB=2×-5/4=-5/2
Hope this helps u
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