sinA+sinB=2 then cosA+cosB=?
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Sin A + Sin B=2
if we consider either SinA or SinB less than 1, then other Sin has to be greater than 1,in order to give the submission equal to 2.
Therefore both has to be equal to 1.
SinA=SinB=1,which implies A=B=90 degrees
Cos(90)=0
Therefore, Cos A+Cos B=Cos(90)+Cos(90)
=0
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