sina=sinb, cosa=cosb, then show that a=2npi+b
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Step-by-step explanation:
A = 2nπ + B
Step-by-step explanation:
The given Trigonometric equations are
sin A = sin B and cos A = cos B
The solution of sin A = sin B is
A = nπ + (-1)ⁿB, n is an integer....(1)
The solution of cos A = cos B is
A = 2nπ ± B , n is an integer........(2)
It is clear that required solution is common to both (1) and (2)
Therefore
A = 2nπ + B
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