SinA, SInB, SinC are in A.P. then a,b,c are in
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Sin a, sin b, sin c, are in a.p
=a, b, c are in a.p
ww know that area of a triangle
=1/2ah , =1/2bh 2=1/2ch3
2 triangle =ah1=bh2=ch3
h1 : h2: h3
=2 triangle /a =2 triangle /b =2 triangle /c
=1/a =1/b=1/c
= abc are in a.p
=h1 , h2 , h3 are in h.p
hence proved
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