sinA=sinB then prove A+B=90
jagritikumari4726:
answer is1
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Answered by
12
Here is the aansweer......
Left hand side ...Put B= 90 - A .....
(SinA + sin (90 - A ) ) / sinA =( sinA + cos A )/sinA ....
= 1 + cotA .....
Right hand side ....similarliy .....
tanA + 2tan( 90 - A ) = tanA + 2 cot A .
........
= 1 + cot A .....
Hence both side are equal .....
Proved ......
Left hand side ...Put B= 90 - A .....
(SinA + sin (90 - A ) ) / sinA =( sinA + cos A )/sinA ....
= 1 + cotA .....
Right hand side ....similarliy .....
tanA + 2tan( 90 - A ) = tanA + 2 cot A .
........
= 1 + cot A .....
Hence both side are equal .....
Proved ......
Answered by
12
ok look at your question first
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