Question

SinA.tan / 1-cos A = 1+sec A

Answer 1

SinA.tan/1-cosA = 1 + secA

or, Sin²A.tan²/1-cos²A = 1² + sec²A [ Squaring both side]
or, Sin²A.tan²/Sin² = 1²+ sec²A [ sin² = 1- cos²]
or, tan² A = 1²+ sec²A
or, tan² A = tan² A [ tan² = 1+sec²] Proved