sinA tanA/1-cosA=1+secA
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Answered by
4
Answer:
Step-by-step explanation:
sinA.tanA/1-cosA
= (sinA.sinA/cosA)/1-cosA
= (sin^2a/cosA)/1-cosA
= (1-cos^2A/cosA/1-cosA
= {(1-cosA1+cosA)/cosA}/1-cosA
= 1+cosA/cosA
= secA+1
it is the prove
Answered by
0
Here is the answer mate
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