sinA upon 1- cosA + cosA upon 1- tanA = cosA + SinA
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Answered by
0
Answer:
sorry what is this
Step-by-step explanation:
Answered by
1
Answer:
Here is the solution -
=(sinA + 1 - cosA) / (cosA - 1 + sinA)
Divide each term by cosA
=(tanA + secA - 1) / (1 - secA + tanA)
=[tanA + secA - ( sec2A−tan2A )] /
( 1 - secA + tanA)
= (tanA+secA)( 1 - secA + tanA )/(1 - secA + tanA)
= tanA + secA
= (sinA / cosA )+ 1 / cosA
= (sinA + 1 )/ cosA
Hence Proved
Hope it will help you
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